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    • M

      1991 AMC 8 Question 16

      Math Problems
      • • • magnificenthorse
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      M

      Thanks for the explanation. I guess I didn’t think that the card had numbers on both sides. But it makes sense now.

    • F

      M1 Final Challenge Q17

      Daily Challenge Course Discussion
      • • • fantasticcrow
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    • victorioussheepV

      The formula A/B-A

      Module 1 Day 15 Your Turn Part 4
      • • • victorioussheep
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      F

      @quacker88 Hi! Thanks for the helpful explanation because I had the same question victorioussheep did. It's just when I tried to solve the problem you gave, I got the answer B/(B-A).

      (1/A-1/B)t=1 Simplifying (1/A-1/B), I get (B-A/AB)t=1 and so t= AB/B-A. t is the time it takes for the first runner to catch up with the second runner. So the number of laps the first runner runs is AB/B-A divided by A which is B/B-A.

      Also, I think how Prof. Loh got A/A-B was by solving for the number of laps the trainer or the second runner was running.

      I don't know if this is correct, but I hope you can look over my work. Thanks!

    • H

      question

      Module 3 Day 2 Challenge Part 3
      • • • hhh
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    • P

      Incorrect Answer for Mini-Question

      Module 4 Day 11 Challenge Part 7
      • • • productiveotter
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      aaronhmaA

      @productiveotter Yes, you're right; it is wrong (see attached screenshot). Unfortunately, it looks like nobody from the Daily Challenge team is fixing this.

      @po @thomas @audrey @debbie Please respond, thank you!

      Mathway.com/Algebra Solution

    • helpfulraccoonH

      has the meeting started yet?

      Comments & Feedback
      • • • helpfulraccoon
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    • F

      Questions...

      Module 1 Day 15 Challenge Part 4
      • • • fantasticcrow
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    • F

      Day 15 Something to Think about

      Module 1 Day 15 Challenge Part 1
      • • • fantasticcrow
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    • F

      M1 Week 3 Challenge Q20

      M1 Algebra Basics
      • • • fantasticcrow
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    • F

      M1 Week 2 Challenge Q20

      M1 Algebra Basics
      • • • fantasticcrow
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      F

      Thanks! i think i kinda got it. Using your way of assuming there are 100 pollywogs and 100 flies, i figured that 17x7=119 which is bigger than 100, so each consuming 7% of the total amount would be impossible. 😅 and that 7%was probably compared to their previous consumption. 😊

    • A

      When do we use stars and bars

      Day 8
      • • • authenticcrane
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      mathnerd_101M

      @authenticcrane If I recall correctly, stars and bars is for both indistinguishable items. Thus your reasoning as to why it is 7 choose 2 is correct. Unfortunately, I do not think you can manipulate stars and bars for items that are distinguishable.

    • RZ923R

      Options

      The Number 42
      • • • RZ923
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    • P

      Week 4 challenge question 10.

      Week 4
      • • • productivemockingbird 0
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      F

      Hi, not a particular geometry pro, but i hope i can help.😊 WechatIMG2.jpeg

    • L

      Weekly Challenge Question

      Week 4
      • • • livelymockingbird 0
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      audreyA

      Screen Shot 2022-08-27 at 11.09.12 AM.png
      Great question!! I've attached a diagram to make things clearer and I'll try to explain it here.

      [Left column] first of all, as you can see, if you graph out all six solutions of (x,y), it forms this region shaped like an isosceles triangle-- in fact, it's a right isosceles triangle with side length 2 (white shaded). The solutions to this question are precisely the lattice points (points with integer coordinates) that are contained within that triangle!

      But why is that?

      [Right column] Well, if you think about it, we start out with a whole lattice grid of possible (x,y). That includes stuff like (x,y) = (-45840, 409574) or (x,y) = (0,0) or (x,y) = (1,2), etc etc etc. In order to narrow down this infinite # of possible (x,y) into the actual solutions, we need to consider the three constraints on (x,y):

      first of all, x >= 1. That's because the problem says that x should be a positive integer, which means it can be 1, 2, 3, ....

      second of all, y >=1. That's because y also has to be a positive integer.

      Finally, we must have x + y <= 4 by the problem statement.

      The basic idea for the algebraic solution is to graph out what each of these three constraints looks like, and "combine" them together. So if you look at the graph for x >= 1, we've shaded all points (x,y) such that x >= 1. Similarly, the pink shading represents all the points such that y >= 1. And the blue shading represents all the points such that x + y <= 4 (to do that, we first graphed the line x + y = 4, and then we shaded in everything underneath it!)

      So now we have three different graphs of shaded regions, each representing different conditions. If we want ALL THREE conditions to be satisfied, all we have to do is "overlay" the graphs on top of each other and figure out what region is shaded in all three graphs! And if we do so, we see that the light yellow triangle is the region of overlap. Therefore, all the lattice points inside that triangle are the answer.

      Hope this made sense to you, and feel free to reach out if you have any further questions! 😄

    • L

      Question

      Module 3 Day 12 Challenge Part 2
      • • • livelymockingbird 0
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      L

      @audrey Thanks! Your explanation has helped.

    • RZ923R

      Test mistake?

      Week 2
      • • • RZ923
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    • I

      I can't figure out how to get the challenge 1 questions supposed to be today for module 0 starting aug 15th. Can someone help me?

      Comments & Feedback
      • • • insightfulporcupine
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      I

      I got it.

    • F

      M0 Week 4 Challenge Q20

      Week 4
      • • • fantasticcrow
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    • T

      Ad?

      Funny
      • • • Todymaster
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      S

      @enlivenedporcupine-0 Yeah that's CSS web development add just skip it sir.

    • S

      Can anyone give me feedback on how can I improve my app{It's a game}

      Programming
      • • • studiouszebra
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      S

      @Desolate_101 I made that using Python and In python I used Tkinter. If you can contribute to this project you or wana tell me something you can contact me a this email : harshsc2007@gmail.com.
      Thank you for checking out my project. After 1 year some one has sent some reply. And now I have stopped development on my project cause of studies. if you want to develop you can contact me at above email and if you want we can partnership in coding. on projects

      Thank You
      Harsh

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