@RZ923 LOL HHHHHH 😁

@RZ923 QUITE TRUE

@versatilemole i could give as many solutions as i can to this problem, and then people can add on solutions and count how many ways we can make 100.

Not really 🙂 Notice how Elmo has three blocks. It wouldn't be $$\binom{9}{3}$$ because you use a separate block every time so you would have to choose the first block, then the second, and so on. Try to see where you can go from there 😉

Note: Sorry this is so late I doubt you're active on this forum anymore.

@knowledgeabledog Thanks!

I am, he kinda cracked at minecraft

@sereneseagull Huh weird I got the same answer and I believe it's a typo...

@Bella Nice! 😄 That's definitely a valid way of doing it-- splitting into cases based on whether the triangles are equilateral, isosceles, or scalene (no two sides with the same lengths) is a good choice, because then it makes it harder to accidentally miss a triangle. Just goes to show that there are often multiple ways to solve a problem!

Does this mean that we can flip the WB block around, and make it to become only BW instead, with the combination
\(BWBWBW\), such that it ends in W?

@Kaiser hello, Im desolate101 looks like you really like Warrior Cats? Me too!