@quacker88 Hi! Thanks for the helpful explanation because I had the same question victorioussheep did. It's just when I tried to solve the problem you gave, I got the answer B/(B-A).

(1/A-1/B)t=1 Simplifying (1/A-1/B), I get (B-A/AB)t=1 and so t= AB/B-A. t is the time it takes for the first runner to catch up with the second runner. So the number of laps the first runner runs is AB/B-A divided by A which is B/B-A.

Also, I think how Prof. Loh got A/A-B was by solving for the number of laps the trainer or the second runner was running.

I don't know if this is correct, but I hope you can look over my work. Thanks!

@quacker88 Thank you very much sir/mam , for checking my answer 😀. No sir/mam I didn't learn relative speeds from modules.