Subcategories

• Day 1

  Modular Arithmetic

  Module 5 Day 1 Challenge Part 1 Module 5 Day 1 Challenge Part 2 Module 5 Day 1 Challenge Part 3 Module 5 Day 1 Challenge Part 4 Module 5 Day 1 Challenge Part 5 Module 5 Day 1 Challenge Part 6 Module 5 Day 1 Challenge Part 7 Module 5 Day 1 Your Turn Part 1 Module 5 Day 1 Your Turn Part 2
  3
  Topics
  5
  Posts

  G

  I think it meant 1 and 0 as that is what the solution said. Also the problem mentioned writing 'ten' and 'one hundred.' Probably just a typo but it was kind of confusing. Please fix this

• Day 2

  Remainders Modulo 3 and 9

  Module 5 Day 2 Challenge Part 1 Module 5 Day 2 Challenge Part 2 Module 5 Day 2 Challenge Part 3 Module 5 Day 2 Challenge Part 4 Module 5 Day 2 Your Turn Part 1 Module 5 Day 2 Your Turn Part 2 Module 5 Day 2 Your Turn Part 3
  6
  Topics
  21
  Posts

  K

  Man this is too hard to understand

• Day 3

  Remainders Modulo 2, 4, and 8

  Module 5 Day 3 Challenge Part 1 Module 5 Day 3 Challenge Part 2 Module 5 Day 3 Challenge Part 3 Module 5 Day 3 Challenge Part 4 Module 5 Day 3 Your Turn Part 1 Module 5 Day 3 Your Turn Part 2 Module 5 Day 3 Your Turn Part 3 Module 5 Day 3 Your Turn Part 4
  7
  Topics
  31
  Posts

  R

  The forum link after the quiz leads to the quiz, not the forum.

• Day 4

  Another Modulus

  Module 5 Day 4 Challenge Part 1 Module 5 Day 4 Challenge Part 2 Module 5 Day 4 Challenge Part 3 Module 5 Day 4 Challenge Part 4 Module 5 Day 4 Challenge Part 5 Module 5 Day 4 Your Turn Part 1 Module 5 Day 4 Your Turn Part 2
  6
  Topics
  17
  Posts

  S

  The reason that the greatest possible sum of A, C and E is 6 instead of 9 is because of the limitation that A+C+E=B+D. Since the greatest value B and D can be is 3, the maximum value that the sum of B+D can be is 6.

  If you set A,C, and E = 3; you'd basically say 3+3+3 = 9 = B+D, which isn't possible since the max of B+D is 6 and 9 > 6.