Subcategories

• Module 5 Day 1 Challenge Part 1

  Last Digit of a Sum of Squares

  0
  Topics
  0
  Posts
  No new posts.
• Module 5 Day 1 Challenge Part 2

  Congruent Numbers

  0
  Topics
  0
  Posts
  No new posts.
• Module 5 Day 1 Challenge Part 3

  Patterns in the Last Digit of a Square

  0
  Topics
  0
  Posts
  No new posts.
• Module 5 Day 1 Challenge Part 4

  Modulo Notation

  1
  Topics
  1
  Posts

  P

  In the solution, it states that 59 and 45 have a difference of 7. This is clearly wrong. It should have stated "For choice ii.), 59 and 45 have a difference of 14, which is a multiple of 7, so this is the correct answer."

• Module 5 Day 1 Challenge Part 5

  Numbers Mod 10

  0
  Topics
  0
  Posts
  No new posts.
• Module 5 Day 1 Challenge Part 6

  Modular Multiplication

  0
  Topics
  0
  Posts
  No new posts.
• Module 5 Day 1 Challenge Part 7

  Negative Remainders

  1
  Topics
  3
  Posts

  

  @Bella Both are actually correct. I believe Professor Loh first found 27 (mod 4) to be 3, and then doubled this to get 6. Professor Loh is emphasizing the simplification step, which makes working with larger numbers easier. And if we simplify this further, 6 is 2 (mod 4). So your calculator is not wrong; 27 + 27 is 2 (mod 4). But noting Professor Loh's strategy will help you solve these types of problems more efficiently 🙂

• Module 5 Day 1 Your Turn Part 1

  Remainder of a Product Mod 11

  1
  Topics
  1
  Posts

  G

  I think it meant 1 and 0 as that is what the solution said. Also the problem mentioned writing 'ten' and 'one hundred.' Probably just a typo but it was kind of confusing. Please fix this

• Module 5 Day 1 Your Turn Part 2

  Solution Using Negative Remainders

  0
  Topics
  0
  Posts
  No new posts.