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• Module 5 Day 4 Challenge Part 1

  Factors of Palindromes

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  a 4-digit palindrome is a number reading the same front to back and back to front. For example, 1221. We can express a 4-digit palindrome as 1000x + 100y+10y+x= 1001x + 110y. finding a common factor we get. 11(91x+10y) 91 and 10 are coprime or relatively prime. Therefore our answer is 11. Also you could use the divisibility test for 11

• Module 5 Day 4 Challenge Part 2

  Factors of 1111

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  @neatlobster it is actually possible to get something with 0's with a number that has no zeros; for example, 51 * 2 = 102, but neither 51 nor 2 have 0s in them.

  Cool observation though!

• Module 5 Day 4 Challenge Part 3

  Solution

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  @quacker88 Ok thank you I got that 🙂

• Module 5 Day 4 Challenge Part 4

  Negative Remainders

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• Module 5 Day 4 Challenge Part 5

  Proof of Solution

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  The reason that the greatest possible sum of A, C and E is 6 instead of 9 is because of the limitation that A+C+E=B+D. Since the greatest value B and D can be is 3, the maximum value that the sum of B+D can be is 6.

  If you set A,C, and E = 3; you'd basically say 3+3+3 = 9 = B+D, which isn't possible since the max of B+D is 6 and 9 > 6.

• Module 5 Day 4 Your Turn Part 1

  Remainders Mod 99

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• Module 5 Day 4 Your Turn Part 2

  Solution Using Remainders Mod 9 and Mod 11

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