Subcategories

• Module 5 Day 2 Challenge Part 1

  Divisibility by 9

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• Module 5 Day 2 Challenge Part 2

  Proof of Trick for Divisibility by 9

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• Module 5 Day 2 Challenge Part 3

  Using the Trick

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  I

  Thanks so much!😊 👏 👏 👏 👏

• Module 5 Day 2 Challenge Part 4

  Casting Out 9's

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  @professionalbronco Yeah! This trick makes finding remainders when dividing by 9 really fast. It's not too common that a problem will require you to find a number \(\pmod{9}\), but it's definitely very useful for this specific case.

• Module 5 Day 2 Your Turn Part 1

  Sum of the Digits of a Number Mod 3

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• Module 5 Day 2 Your Turn Part 2

  Relationship of Remainders Mod 9 and Mod 3

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• Module 5 Day 2 Your Turn Part 3

  Casting Out 3's

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  @neatlobster Please take a look at your other post where I answered your question. 🙂 https://forum.poshenloh.com/topic/707/question-what-does-it-mean-by-then-the-value-of-a-digit-in-its-place-is-exactly-the-sum-you-get-when-you-add-up-these-stray-1-s