Could you post how you did it? Considering you said "easier way," you should already have a solution. How did you do it?
As a hint for a quicker way to do it:
I would first use the sum of factors formula:
Let
$$n=p_1 ^{a_1}p_2^{a^2}p_3^{a_3} \ldots p_k^{a_k}
$$
(right now latex isn't displaying properly; sometimes it will have a line of math in plain text below the math in latex. Hope you still understand what I'm trying to show you)
The sum of the factors of
$$n
$$
is
$$(p_1^0+p_1^1+p_1^2+ \ldots + p_1^{a_1})(p_2^0+p_2^1+p_2^2+ \ldots + p^{a_2})\ldots (p_k^0+p_k^1+p_k^2 + \ldots + p_k^{a_k})
$$
I would then prime factorize each of the answer choices and then apply the formula.
Hope this helps! 😊
