New method for Your Turn in Module:1 Day:14

• Given: There are 2 people in race.
Trainer finishes 1 lap in 75 seconds.
Olympic runner finishes 1 lap in 57 seconds.

Suppose race track length = 1425m.

I selected 1425 because 1425 is lcm of 57 and 75.

Speeds:
1) Trainer = 19 m/s
2) Olympic runner = 25m/s

Relative speeds:
1) Trainer = 0 m/s (Trainer is stationary)
2) Olympic runner = 6 m/s

Distance/Speed = Time
Assume Trainer is at the start of the lap and is stationary.

Time taken by Olympic runner to complete the lap and to catch trainer who is standing at the start of the lap = Time to catch up.

Time to catch up : 1425m/6m/s = 237.5 seconds

It means, say race starts time T = 0 then, when T = 237.5 s. The overlap will happen.

So Trainer need 75 seconds for 1 lap. Then how many laps in 237.5 seconds.
Number of Trainer laps = 237.5/75 = 3.17(Approximately)

• Given: There are 2 people in race.
Trainer finishes 1 lap in 75 seconds.
Olympic runner finishes 1 lap in 57 seconds.

Suppose race track length = 1425m.

I selected 1425 because 1425 is lcm of 57 and 75.

Speeds:
1) Trainer = 19 m/s
2) Olympic runner = 25m/s

Relative speeds:
1) Trainer = 0 m/s (Trainer is stationary)
2) Olympic runner = 6 m/s

Distance/Speed = Time
Assume Trainer is at the start of the lap and is stationary.

Time taken by Olympic runner to complete the lap and to catch trainer who is standing at the start of the lap = Time to catch up.

Time to catch up : 1425m/6m/s = 237.5 seconds

It means, say race starts time T = 0 then, when T = 237.5 s. The overlap will happen.

So Trainer need 75 seconds for 1 lap. Then how many laps in 237.5 seconds.
Number of Trainer laps = 237.5/75 = 3.17(Approximately)

• @studiouszebra You need to mention @debbie, she's the head mod and answers most questions. Personally this makes a lot of sense for me, but my module 1 has long expired, so I can't go back in and check which answer's right