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Why not the other way around?

Module 1 Day 13 Your Turn Part 2
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  • A
    aaronhma M1★ M2★ M3★ M4★ M5★
    last edited by May 14, 2021, 1:57 AM

    Prof. Loh says that since we're trying to drain the pool and the filling the pool is working against it, the equation is:

    1185+174−1x=1111\frac{1}{185} + \frac{1}{74} - \frac{1}{x} = \frac{1}{111}1851​+741​−x1​=1111​

    By similar logic, we're trying to fill the pool, and draining the pool is working against it, so the equation is:

    1x−174−1185=1111\frac{1}{x} - \frac{1}{74} - \frac{1}{185} = \frac{1}{111}x1​−741​−1851​=1111​

    Are these two equivalent to each other? Thanks! 🙂

    Q 1 Reply Last reply May 14, 2021, 9:43 PM Reply Quote 1
    • Q
      quacker88 MOD @aaronhma
      last edited by May 14, 2021, 9:43 PM

      Really good idea you have there, @aaronhma !

      One thing though (soo close!)-- since you're kinda looking at the problem from the perspective of the filling pipe, we actually have to flip the sign of the 1111\frac{1}{111}1111​. Here's why:

      Let's look at the first equation:

      1185+174−1x=1111\frac{1}{185} + \frac{1}{74} - \frac{1}{x} = \frac{1}{111}1851​+741​−x1​=1111​

      What this equation literally means is that, in 111 minute, the large pipe drains 1185\frac{1}{185}1851​ of the pool, the small pipe drains 174\frac{1}{74}741​ of the pool, and the filling pipe fills or "un-drains" 1x\frac{1}{x}x1​ of the pool, which is why we subtract the 1x\frac{1}{x}x1​. This altogether is equal to draining 1111\frac{1}{111}1111​ of the pool.

      But looking at the second equation, which is from the perspective of the filling pipe, we have:

      1x−174−1185=1111\frac{1}{x} - \frac{1}{74} - \frac{1}{185} = \frac{1}{111}x1​−741​−1851​=1111​

      This equation says that, in 111 minute, the filling pipe fills 1x\frac{1}{x}x1​ of the pool, the small pipe drains or "un-fills" 174\frac{1}{74}741​ of the pool, which is why we subtract 174\frac{1}{74}741​, the large pipe drains or "un-fills" 1185\frac{1}{185}1851​ of the pool, which is why we subtract1185\frac{1}{185}1851​.

      But here's the catch: this altogether is equal to draining 1111\frac{1}{111}1111​ of the pool. We have "un-filled" the pool by that much. This means we have less water than when we started.

      So, the correct equation would be actually equal to −1111-\frac{1}{111}−1111​:

      1x−174−1185=−1111\frac{1}{x} - \frac{1}{74} - \frac{1}{185} = -\frac{1}{111}x1​−741​−1851​=−1111​

      Notice how this is exactly the same as Prof. Loh's equation but multiplied all the way on both sides by −1-1−1.
      Really great thinking you did there, and it really goes to show how many different ways there are to solve the same problem! Well done 🙂

      A 1 Reply Last reply May 14, 2021, 9:46 PM Reply Quote 2
      • A
        aaronhma M1★ M2★ M3★ M4★ M5★ @quacker88
        last edited by May 14, 2021, 9:46 PM

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