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    Why not the other way around?

    Module 1 Day 13 Your Turn Part 2
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    • aaronhmaA
      aaronhma M1★ M2★ M3★ M4★ M5★
      last edited by

      Prof. Loh says that since we're trying to drain the pool and the filling the pool is working against it, the equation is:

      $$\frac{1}{185} + \frac{1}{74} - \frac{1}{x} = \frac{1}{111}$$

      By similar logic, we're trying to fill the pool, and draining the pool is working against it, so the equation is:

      $$\frac{1}{x} - \frac{1}{74} - \frac{1}{185} = \frac{1}{111}$$

      Are these two equivalent to each other? Thanks! 🙂

      quacker88Q 1 Reply Last reply Reply Quote 1
      • quacker88Q
        quacker88 MOD @aaronhma
        last edited by

        Really good idea you have there, @aaronhma !

        One thing though (soo close!)-- since you're kinda looking at the problem from the perspective of the filling pipe, we actually have to flip the sign of the \(\frac{1}{111}\). Here's why:

        Let's look at the first equation:

        $$\frac{1}{185} + \frac{1}{74} - \frac{1}{x} = \frac{1}{111}$$

        What this equation literally means is that, in \(1\) minute, the large pipe drains \(\frac{1}{185}\) of the pool, the small pipe drains \(\frac{1}{74}\) of the pool, and the filling pipe fills or "un-drains" \(\frac{1}{x}\) of the pool, which is why we subtract the \(\frac{1}{x}\). This altogether is equal to draining \(\frac{1}{111}\) of the pool.

        But looking at the second equation, which is from the perspective of the filling pipe, we have:

        $$\frac{1}{x} - \frac{1}{74} - \frac{1}{185} = \frac{1}{111}$$

        This equation says that, in \(1\) minute, the filling pipe fills \(\frac{1}{x}\) of the pool, the small pipe drains or "un-fills" \(\frac{1}{74}\) of the pool, which is why we subtract \(\frac{1}{74}\), the large pipe drains or "un-fills" \(\frac{1}{185}\) of the pool, which is why we subtract\(\frac{1}{185}\).

        But here's the catch: this altogether is equal to draining \(\frac{1}{111}\) of the pool. We have "un-filled" the pool by that much. This means we have less water than when we started.

        So, the correct equation would be actually equal to \(-\frac{1}{111}\):

        $$\frac{1}{x} - \frac{1}{74} - \frac{1}{185} = -\frac{1}{111}$$

        Notice how this is exactly the same as Prof. Loh's equation but multiplied all the way on both sides by \(-1\).
        Really great thinking you did there, and it really goes to show how many different ways there are to solve the same problem! Well done 🙂

        aaronhmaA 1 Reply Last reply Reply Quote 2
        • aaronhmaA
          aaronhma M1★ M2★ M3★ M4★ M5★ @quacker88
          last edited by

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