Stars and Bars - AMC 8 Prep #24

[RZ923]

I like to think of it this way:
If you have nonnegative numbers, they can be 0. So I just add a non-existent Star for each pirate and it will be 4 bars and 13 stars, meaning there’s 12 gaps (all have to be at least 1 star). So it will be 12 choose 4.

[sqwishy]

@RZ923 Wow, that's a great explanation!!

[RZ923]

@sqwishy thx