??? That just completely ignores the possibility of the two lower nodes being different colors, which isn't right, no?

Hold up
That just completely ignores the possibility of the two lower nodes being different colors, which isn't right, no?

@TheBladeDancer Hi again! The solution is counting these two separate cases: Case 1.) where the lower two secondfrombottom nodes are the \(\textcolor{red}{\text{same}}\) color, and Case 2.) where the lower two secondfrombottom nodes are \(\textcolor{red}{\text{different}}\) color.
For Case 1: There were \(48\) ways to color the top six nodes (with the two bottom nodes the same color)
For Case 2: There were \(96\) ways to color the top six nodes (with the two bottom nodes different color).
In the final formula, the \(48\) is multiplied by \(2\) because there are two options for the very bottom node color (e.g. \(\textcolor{green}{\text{green}}\) and \(\textcolor{orange}{\text{yellow}.})\) The \(96\) isn't multiplied by anything, because if you already have two colors for the secondfrombottom nodes, then there's only one choice for the very last bead's color (in this example, \(\textcolor{orange}{\text{yellow}}).\)
$$ 48 \times 2 + 96 = \boxed{192}$$That's how the answer was found.