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    Why is it that when your radius grows by 1 your circumference expands by approximately 6.28?

    Module 0 Day 10 Challenge Part 4
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    • M
      minji MOD M0 M1 M2 M3 M4 M5
      last edited by debbie

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      • debbieD
        debbie ADMIN M0★ M1 M5
        last edited by debbie

        [Originally posted in the Discussions]

        Module 0 Week 3 Day 10 Challenge Explanation Part 3

        Why is it that when your radius grows by 1 your circumference expands by approximately 6.28? Please help.

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        • debbieD
          debbie ADMIN M0★ M1 M5
          last edited by

          🙂 This is a really cool shortcut!

          Let's start with a radius of length 1 and increase to a radius of 2. The circumference goes from

          2π(1) to 2π(2)

          2π → 4π

          The increase in circumference is 2π, and since π = 3.1415.... (Actually, go see the other Discussion on this lesson to see better approximations for π!), then 2π = 6.28.....

          I like to use variables because they are more powerful tools. You can use them to generalize to all sorts of numbers.

          Let's start from a radius of r, and go to a radius of (r + 1). The circumference changes from

          2πr → 2π (r + 1)

          2πr → 2πr + 2π

          The difference in circumference is 2π = 6.28....

          So it doesn't matter what value we use for r, the radius!

          Happy Learning

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