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    How did we know to just multiply the 18 and the 8 by 0.5 and 6 and be done?

    Module 2 Day 12 Your Turn Part 2
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    • The Blade DancerT
      The Blade Dancer M0★ M1★ M2★ M3★ M4 M5
      last edited by debbie

      Module 2 Week 3 Day 12 Your Turn Question

      Uhhhhhhhh... answer was never really stated. How did we know to just multiply the 18 and the 8 by 0.5 and 6 and be done?

      The Blade Dancer
      League of Legends, Valorant: Harlem Charades (#NA1)
      Discord: Change nickname if gay#7585

      debbieD 1 Reply Last reply Reply Quote 2
      • debbieD
        debbie ADMIN M0★ M1 M5 @The Blade Dancer
        last edited by debbie

        @TSS-Graviser I think you are asking about the Your Turn question, am I right? (Not the mini-question at the end.) How about we go over the thing one more time, from beginning to end, with the help of some little diagrams and our Expii colors?

        We are trying to find the area of this tangential quadrilateral (note that this is different from a cyclic quadrilateral, which is inside a circle). All we know about this shape is that two opposite sides have length \(8\) and \(18,\) and the radius of the circle is \(6.\)

        M2W3D12-your-turn-solution1.png

        Let's color these four triangles like so. Since the radii are altitudes of each triangle, all we have to do in order to find the area of the entire thing is to find out the sum of the bases of all the triangles.

        M2W3D12-your-turn-solution2.png

        $$ \text{ Area of triangle } = \frac{1}{2} \times \text{ base } \times \text{ height} $$
        $$ \text{ Area of whole thing } = \text{ Area of } \left( \textcolor{green}{\text{green triangle}} + \textcolor{purple}{\text{ purple triangle }} + \textcolor{blue}{\text{ blue triangle }} + \textcolor{orange}{\text{ orange triangle }} \right) $$

        $$ \text{ Area of whole thing } = \frac{1}{2} \times 6 \times \left( \textcolor{green}{\text{green base}} + \textcolor{purple}{\text{ purple base }} + \textcolor{blue}{\text{ blue base }} + \textcolor{orange}{\text{ orange base }} \right) $$

        Note that we only need to know the sum of the bases, not necessarily the length of each base!

        Now, let's form kites by drawing all the altitudes to each side. We can use the fact that kites have two pairs of sides the same length to show that both of these \( \textcolor{red}{\text{ red segments}}\) have the same length (let's call it \(a.\))

        M2W3D12-your-turn-solution3a.png

        Similarly, let's call the remaining segment of the left side \(b,\) and we know that there is a matching segment of length \(b\) on the other side of the bottom-left kite:

        M2W3D12-your-turn-solution4.png

        This leaves us with a segment of length \(18 -b,\) but we know that there is another matching segment of length \(18-b\) on the other side, leaving us with the last section of length \(8-a.\)

        M2W3D12-your-turn-solution5.png

        Taking a look at just these two green triangles, we notice that the sum of the green bases is equal to
         

        $$ a + b + ( 8-a) + (18-b) = 8 + 18 $$
        $$= 26$$

        M2W3D12-your-turn-solution6.png

        This is exactly the same as the sum of the bases of the two other triangles, which we'll color in purple.

        M2W3D12-your-turn-solution7.png

        In fact, if we remember that this fact is true for tangential quadrilaterals, then we can do the entire question in just one step: we know that two opposite bases sum to \(26,\) so the other two opposite bases sum to \(26,\) and the area of the entire quadrilateral is just

        $$ \text{ Area of whole thing } = \frac{1}{2} \times 6 \times \left( \textcolor{green}{\text{green bases}} + \textcolor{purple}{\text{ purple bases }} \right) $$

        $$ = \frac{1}{2} \times 6 \times (26 + 26) $$
        $$ = 6 \times 26 $$
        $$ = \boxed{156} $$

        🙂

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        • The Blade DancerT
          The Blade Dancer M0★ M1★ M2★ M3★ M4 M5
          last edited by

          uhhh I think it was the mini question sorry

          The Blade Dancer
          League of Legends, Valorant: Harlem Charades (#NA1)
          Discord: Change nickname if gay#7585

          debbieD 1 Reply Last reply Reply Quote 1
          • debbieD
            debbie ADMIN M0★ M1 M5 @The Blade Dancer
            last edited by

            @TSS-Graviser Are you talking about the mini-question from Day 12, Your Turn Part 2?
            Your original question was, "How did we know to just multiply the 18 and the 8 by 0.5 and 6 and be done?" Could you please explain a little more about what you are wondering about? 🙂

            temp-screenshot-m2w3d12-y-part-2.png

            1 Reply Last reply Reply Quote 1
            • The Blade DancerT
              The Blade Dancer M0★ M1★ M2★ M3★ M4 M5
              last edited by

              Oh wait I'm really confused never mind sorry

              The Blade Dancer
              League of Legends, Valorant: Harlem Charades (#NA1)
              Discord: Change nickname if gay#7585

              debbieD 1 Reply Last reply Reply Quote 1
              • debbieD
                debbie ADMIN M0★ M1 M5 @The Blade Dancer
                last edited by

                @TSS-Graviser 🤸 It's all good! 🤸

                1 Reply Last reply Reply Quote 1

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