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    Multiplication Method

    Module 3 Day 12 Challenge Part 1
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    • F
      fantasticcrow M0 M1★ M3 M5
      last edited by

      I know Prof. Loh mentioned that straight multiplication doesn't work, but I think this way of multiplication might?

      For the first vertex, there are 3 choices for what color it might be.

      For the second vertex, there are 2 choices- the choices being the colors that were not the one selected for the first vertex.

      For the third vertex, there is supposed to be 2 choices, but because we're concerned about whether its color is the same as that of the first vertex, we can split it into 2 cases: one in which they're the same (1 choice of color for that), and the other in which the colors are different (1 choice of color for that).

      If vertex 1 and vertex 3 have the same color, then there are 2 choices for the color of vertex 4.

      If the colors are different, there is only 1 choice for the color of vertex 4.

      Therefore, the answer is 3x2x(1+2)=18.

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      • F
        fantasticcrow M0 M1★ M3 M5
        last edited by

        Actually, never mind. I just realized that Prof. Loh just explained it in the next part.

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