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    Seeking clarification about the solution

    Positive Integers Only
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    • eminentcoyoteE
      eminentcoyote M0 M1 M2 M3 M4 M5
      last edited by

      The problem at the end of explanation #2 seems to overlook that no possible values of a are integers.

      If you calculate each value of a, they come out to be 67/6, 35/6, 25/6, and 17/6. Their sum is 24, but none of them are integers. So there are no possible integer values that satisfy that equation.

      The solution uses a trick to calculate the sum of all possible values without actually finding the values of a. So it overlooked the fact that there are no integer values of a.

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