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    Wrong answer to the mini question.

    Revisiting GCDs
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      thoughtfulmongoose M2★ M3★ M4★ M5★
      last edited by

      a=4
      b=2
      Then gcd(a, b)=2 and gcd(a, 2b)=4!!!

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      • S
        stupendousdingo M0 M2 M3 M4 M5 @thoughtfulmongoose
        last edited by

        @thoughtfulmongoose Let a=2x and b=2y, then the question is asking for the GCD of 2x and 4y. Obviously 2 is a common divisor, but we don't know if x has any more 2s in it. If x has one more factor of 2 and y has none then the greatest common divisor is 4. So the answer should be NEI(not enough info)

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