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    Why does Prof. Loh divide pi/2 by sqrt 3 and not something else??

    Module 2 Day 9 Your Turn Part 2
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    • The Blade DancerT
      The Blade Dancer M0★ M1★ M2★ M3★ M4 M5
      last edited by debbie

      Module 2 Week 3 Day 9 Your Turn Explanation Part 2

      Why divide not subtract?

      The Blade Dancer
      League of Legends, Valorant: Harlem Charades (#NA1)
      Discord: Change nickname if gay#7585

      debbieD 1 Reply Last reply Reply Quote 2
      • debbieD
        debbie ADMIN M0★ M1 M5 @The Blade Dancer
        last edited by debbie

        @TSS-Graviser It's because the question was asking for the ratio of the dough that goes toward the circular cookies. So we want

        $$ \frac{\text{area of circular wedges}}{\text{area of equilateral triangle}} $$

        To find the area of the equilateral triangle, we recall that we know the ratios of the height of the equilateral triangle to its leg. In fact, that was covered in this forum post.

        M2W1D1-30-60-90-triangle-proportions.png

        So altitude of an equilateral triangle is equal to \( \sqrt{3} \times \frac{\text{side}}{2} \), which means the area of the equilateral triangle is equal to

        $$\begin{aligned} \text{ area of triangle } &= \frac{1}{2} \times \text{ base} \times \text{ height} \\ &= \frac{1}{2} \times 2 \times \sqrt{3} \\ &= \sqrt{3} \\ \end{aligned} $$

        Inside the equilateral triangle, there are three wedges of cookie, each with an angle of \(60^{\circ}.\)

        M2W3D9-y-forum-question-why-divide-sqrt-3-whole-triangle.png

        Put together, the wedges make up half of a circle with radius \(1!\)

        M2W3D9-y-forum-question-why-divide-sqrt-3-half-circle.png

        Since the area of a circle with radius \(1\) is \(\pi ,\) the cookie area is \(\frac{\pi}{2}.\)

        And since we know the area of the cookie and the area of the triangle, we can find the answer, which is the ratio of two:

        $$ \frac{\text{cookie area}}{\text{triangle area}} = \frac{\frac{\pi}{2}}{\sqrt{3}}$$

        I hope this helps! 🙂

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