BOGUS PROOFS
-
post all of your bogus proofs here ;D other people can try to guess where you went wrong
-
@energizedpanda I'm going to prove that
$$\frac12 < \frac14 $$we have:
$$1<2 $$ $$1 \cdot\log_4 0.5 < 2 \cdot \log_4 0.5 $$Now, using log rules
$$\log_4 0.5^1 < \log_4 0.5^2 $$ $$ 0.5^1 < 0.5^2 $$ $$0.5 < 0.25 $$Q.E.D.
Wait a minute, that's not right! Where did I go wrong? -
Proof that:
\(2=1\)\(a=b\)
\(a^2 = ab\)
\(a^2-b^2=ab-b^2\)
\((a+b)(a-b)=b(a-b)\)
\(a+b=b\)
\(2b=b\)
\(2=1\) -
@rz923 haha you divided by a-b which is 0 since a = b :DD
-
@energizedpanda
Yeahhh -
@gloriouswolf log 4 (0.5) is negative so you have to reverse the sign
-
@energizedpanda
Wow... you are fast... -
1x0=0
2x0=0easiest bogus proof ever