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    Final Review Question 19 and 20

    M3 Combinatorics Tools
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      spaceblastxy1428 M1★ M3★ M4 M5★
      last edited by spaceblastxy1428

      Why can't you rotate the table to get the same arrangement if you do \(A_1, A_2, B_1, B_2, C_1, C_2\) and \(C_2, A_1, A_2, B_1, B_2, C_1\) when you are counting clockwise to get an answer of 48?

      debbieD 2 Replies Last reply Reply Quote 2
      • debbieD
        debbie ADMIN M0★ M1 M5 @spaceblastxy1428
        last edited by

        @spaceblastxy1428 Thanks for asking! Since this is a exam question, in the interest of keeping exam solutions private, we'll answer by email instead of here on the forum. Thanks for your understanding!

        1 Reply Last reply Reply Quote 1
        • debbieD
          debbie ADMIN M0★ M1 M5 @spaceblastxy1428
          last edited by

          @spaceblastxy1428 Hi there, since this doesn't give away the solution, I'll answer here. 🙂 The question was written with the intention of not having rotational symmetry. Pretend the chairs are numbered from \(1\) to \(6,\) so that if you rotate a seating arrangement, then it's considered a new arrangement. We can clarify this in the question statement. Thanks for asking!

          1 Reply Last reply Reply Quote 2

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