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    1 to the 0 power

    Math Problems
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    • The Blade DancerT
      The Blade Dancer M0★ M1★ M2★ M3★ M4 M5
      last edited by

      I mean, there's also like continuing a pattern, but shouldn't math be applied and not just working in theory?

      The Blade Dancer
      League of Legends, Valorant: Harlem Charades (#NA1)
      Discord: Change nickname if gay#7585

      debbieD 1 Reply Last reply Reply Quote 2
      • The Blade DancerT
        The Blade Dancer M0★ M1★ M2★ M3★ M4 M5
        last edited by

        We already have a ton of exceptions in math, and including one here wouldn't be a problem. Besides, it would be possible to derive this exception easily.

        The Blade Dancer
        League of Legends, Valorant: Harlem Charades (#NA1)
        Discord: Change nickname if gay#7585

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        • debbieD
          debbie ADMIN M0★ M1 M5 @The Blade Dancer
          last edited by

          @The-Rogue-Blade Good point! In practice, \(x^0 = 1\) works in the sense that it's better than \(x^0 = 0,\) because if \(x^0 = 0,\) then we get

          $$ \textcolor{red}{x^0} \times x^4 = 0 $$

          $$ \textcolor{red}{0} \times x^4 = 0 $$

          which is a bit strange, since \(\textcolor{red}{x^0}\) would be able to have this destructive property of obliterating all other exponents. 💥 💫

          Additionally, when we prime factorize a number, like \(60,\)

          $$ 60 = 2^2 \times 3^1 \times 5^1 $$

          we might want to be able to list them out with all primes as a sort of basis, like

          $$ 60 = 2^2 \times 3^1 \times 5^1 \times \textcolor{red}{7^0} \times \textcolor{red}{11^0} \times \textcolor{red}{13^0} \ldots $$

          We would only be able to do so if we define \(x^0\) to equal \(1.\)

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          • The Blade DancerT
            The Blade Dancer M0★ M1★ M2★ M3★ M4 M5
            last edited by

            Well, that's just my point of view on this. I was also about to ask why the code was weird 🤣

            The Blade Dancer
            League of Legends, Valorant: Harlem Charades (#NA1)
            Discord: Change nickname if gay#7585

            debbieD 1 Reply Last reply Reply Quote 2
            • debbieD
              debbie ADMIN M0★ M1 M5 @The Blade Dancer
              last edited by

              @The-Rogue-Blade It might be because it's a fresh post, and it takes awhile for the site to render the code...? I'm not sure, but refreshing often fixes the problem! 🙂

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              • T
                thomas MOD
                last edited by

                Interesting discussion! What do you guys think \(0^0\) is?

                Potato2017P 1 Reply Last reply Reply Quote 2
                • The Blade DancerT
                  The Blade Dancer M0★ M1★ M2★ M3★ M4 M5
                  last edited by

                  @thomas 0

                  The Blade Dancer
                  League of Legends, Valorant: Harlem Charades (#NA1)
                  Discord: Change nickname if gay#7585

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                  • Potato2017P
                    Potato2017 M5★ @thomas
                    last edited by

                    @thomas It's probably undefined. Since 0^x = 0 and x^0=1 for all nonzero x, if x were to be 0, we would have 0=1, which is very, uh,

                    $$$$
                    $$$$
                    $$$$

                    let's just not think about that.

                    The best Potato
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                    -Potato2017

                    T 1 Reply Last reply Reply Quote 2
                    • T
                      thomas MOD @Potato2017
                      last edited by thomas

                      @Potato2017 Interesting! It seems like it's unclear if we can even do it at all...

                      Would perhaps this graph change your mind?

                      f78f3099-ddff-490b-8fa2-7e56dfb62f58-image.png

                      This is a graph of the function \(x^x\). What this graph is saying is that if you look at \(1^1\), \(0.1^{0,1}\), \(0.01^{0.01}\), ... these numbers get closer and closer to \(1\). Do you think that means that \(0^0\) should be \(1\)? Why or why not?

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                      • RZ923R
                        RZ923 M0★ M2★ M3★ M4★ M5
                        last edited by

                        @The-Blade-Dancer
                        I came up with another way of explaining why \(1^0\) is \(1\). It had something to do with Place Value.
                        Let’s just look at base 10.
                        Any number, say \(1729\), can be represented with powers of 10.
                        For example, the \(1\) represents \(1000\), or \(1 \times 10^3\). The \(7\) represents \(7 \times 10^2\), and the \(2\) represents \(2 \times 10^1\).
                        Now let’s look at the \(9\). What does it represent.
                        Continuing our pattern, it represents \(9 \times 10^0\).
                        So \(10^0\) must be one. If it’s \(0\), then we don’t have place value.
                        Hope that helps 🙂

                        Very Interesting

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                        • The Blade DancerT
                          The Blade Dancer M0★ M1★ M2★ M3★ M4 M5
                          last edited by The Blade Dancer

                          90932943-282d-4d64-ac2e-ec68aa50d91c-image.png

                          lol you have a point there

                          The Blade Dancer
                          League of Legends, Valorant: Harlem Charades (#NA1)
                          Discord: Change nickname if gay#7585

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