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• Module 4 Day 14 Challenge Part 1

  Finding the Intersection Point of Two Lines

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  You can see that with graph paper that B is slightly longer.

• Module 4 Day 14 Challenge Part 2

  Slope-Intercept Form of Equation of a Line

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  If you already have the x and y intercepts, you can use a formula to figure the equation out

  $${x\over a}+{y\over b}={1} $$

  "a" would be the x intercept and "b" would be the y intercept

  $${x\over 1.5}+{y\over -3}={1} $$

  multiply 2 on the top and bottom of

  $${x\over 1.5} $$

  So you get

  $${2x\over 3} $$

  Then using this info we get

  $${2x\over 3}+{y\over -3}=1 $$ $${2x-y\over 3}=1 $$ $${2x-y}=3 $$

  After rearranging things, we get

  $$y={2x-3} $$

  And that's it!

• Module 4 Day 14 Challenge Part 3

  Trick Using Similar Triangles

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• Module 4 Day 14 Challenge Part 4

  Trick Using Similar Triangles

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• Module 4 Day 14 Your Turn Part 1

  Distance Between Point and a Line

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  D

  @rz923 Thanks so much! I've fixed this now. 🙂 I really appreciate you letting us know 🙂

• Module 4 Day 14 Your Turn Part 2

  Equation of Perpendicular Line, Solving System of 2 Equations

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• Module 4 Day 14 Your Turn Part 3

  Another Solution Using Similar Triangles

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• Module 4 Day 14 Your Turn Part 4

  Another Solution Using Similar Triangles

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