@tidyboar
By the way, here is the code for the quadratic formula above

\\(r=-\frac{b}{2a}\textcolor{red}{-\pm}\frac{\sqrt{b^2-4ac}}{2a}\\)

\(r=-\frac{b}{2a}\textcolor{red}{-\pm}\frac{\sqrt{b^2-4ac}}{2a}\)