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• Module 3 Day 7 Challenge Part 1

  Brute Force Method of Adding Chooses

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• Module 3 Day 7 Challenge Part 2

  Patterns in Even and Odd Entries of Pascal's Triangle

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  @professionalbronco No worries about the bump! Super glad to see you learning so much, and even coming back to correct an old post 🙂

  You're absolutely right, these sums don't converge, so you can't manipulate them as if they were actual equations. In fact, \(1+2+3+4+...=-\frac{1}{12}\) is just really misleading in general. While \(-\frac{1}{12}\) is related to it, it's not really "equal" to it in the normal sense.

  Great job once again!

• Module 3 Day 7 Challenge Part 3

  Sum of Numbers in a Row of Pascal's Triangle

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  "These numbers are not circled, but they are circled." --Prof Loh
  10000 iq quote

• Module 3 Day 7 Challenge Part 4

  Relationship of Pascal's Triangle to Binomial Expansions

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• Module 3 Day 7 Challenge Part 5

  Alternate Solution

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• Module 3 Day 7 Your Turn Part 1

  Powers of 11

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  @aaronhma Haha...I believe there is no rain-dropping sound in Module 1, but you will hear them in Module 3, which is the only Module I knew that has that effect.

• Module 3 Day 7 Your Turn Part 2

  Solution Using Binomial Coefficients

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  When you multiply 11 by something, it basically equals to \(\text{that number} \times 10 + \text{that number}\).
  So it is that number plus that number 'shifted' 1 place to left.
  So if that number is 121, it would look something like this:
  121
  +121
  So it is \(\text{(hundreds)} + \text{(tens + hundreds)} + \text{(ones + tens)} + \text{(ones)}\), which is the same as Pascal's triangle!
  Then just clear up the mess and you get a number.