@The-Rogue-Blade This is a good question! If we take the Power of a Point Theorem literally, then the segments that we are multiplying together should live up to the name "Power of a Point"; they should all emanate from the same point. In the above illustration, the correct answer is shown: $$ CF \times CE = (BC)^2 $$ Now consider \(\overline{AE}\) and \(\overline{AF};\) these segments emanate from point \(A,\) but the segment \(\overline{BC}\) emanates from a \(\textcolor{red}{\text{different}}\) point, \(C.\) We have not one point, but \(2\) points. Unfortunately, it's not called "Power of Two Points," so $$ AE \times AF \neq (BC)^2 $$