Subcategories

• Module 2 Day 4 Challenge Part 1

  Area of a Parallelogram in Parts

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  Quick reminder on the mini question on the challenge explanation. If you got this wrong and are like me and can't read directions, it says check all that are true, so that may be why 🙂

• Module 2 Day 4 Challenge Part 2

  3-5-7 Triangle, Area of a Triangle

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  This is cross-linking back to the Module 0 Week 1 Day 1 Forum Topic of the same title! 🙂

• Module 2 Day 4 Challenge Part 3

  Alternate Solution by Extended Lines

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  @victorioussheep Oh okay, sounds good! 😄

• Module 2 Day 4 Your Turn Part 1

  Isosceles Trapezoid With Diagonals

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  No new posts.
• Module 2 Day 4 Your Turn Part 2

  Technique of Dropping an Altitude, 30°-60°-90° Triangle

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  @debbie What a bunch of 30∘−60∘-90∘ right triangles!

• Module 2 Day 4 Your Turn Part 3

  Using Variables to Solve For Area

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  In this case, since x represents the length of the diagonal of the trapezoid, it wouldn't be possible for x/2 to be a negative number. In general, though, you are right; this equation falls in to the category of "quadratic equations," which have an x-squared term. It's possible to show that quadratic equations always have two solutions.

  You can see Prof. Loh talk about a cool way of solving quadratic equations which he came up with while developing Module 4: Algebra Tools. You can also read more about him and his quadratic method in this NYT article.

  Happy Learning!

  The Daily Challenge Team