Subcategories

• Module 2 Day 1 Challenge Part 1

  Exterior and Interior Angles of Polygons, 3-4-5 and Equilateral Triangles

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  @RZ923 Yes, thank you! This has been on our list of things to do for awhile, but we haven't had a chance to get to it yet. Thanks for the reminder. 🙂

• Module 2 Day 1 Challenge Part 2

  Area and Altitude of an Equilateral Triangle, Pythagorean Theorem

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  @victorioussheep the mini-question!

• Module 2 Day 1 Challenge Part 3

  Another way, Using Similar Triangles and Scaling

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• Module 2 Day 1 Challenge Part 4

  30°-60°-90° Triangles

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  @RZ923 Thanks for asking! I haven't gotten a chance to reply to this yet, but in the meantime, there are some more forum posts about this same topic ~~ Please check them out! 🙂

  https://forum.poshenloh.com/topic/84/formula-to-figure-out-why-the-equilateral-triangle-area-formula-works

  https://forum.poshenloh.com/topic/96/re-question

• Module 2 Day 1 Your Turn Part 1

  3 - 5 - 120° Triangle, Extending Lines in a Figure

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  @victorioussheep Yes the 45-45-90 triangle is very important too!
  The biggest takeaway from these triangle is that the RATIOS are always the same. In every 30-60-90 triangle, the ratio of the hypotenuse to the short leg (the side opposite 30 degree) is ALWAYS 2:1.
  bc96b34f-76c2-4774-b5d0-0a510ac6857e-image.png
  These are all 30-60-90 triangles! The greatest thing is that you know that whenever you see 30-60-90, the ratios are \(1:\sqrt{3}:2\), but the reverse is also true! Whenever you see that the ratio is \(1:\sqrt{3}:2\), it's a 30-60-90 triangle!

• Module 2 Day 1 Your Turn Part 2

  Pythagorean Theorem; 3-5-7 Triangle

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  @The-Blade-Dancer (long leg)^2 = (3^2) - (3 / 2)^2 which simplifies to 3/2√3