<![CDATA[There was a typo...]]>I'm confused. The answer was n(n+1), but the options were:
i.) 1/(n(n-2))
ii.)1/(2n-2)
iii.)1/(2n)
iv.)1/(n(n-1))

I guessed iv.) even though none of them seemed to work and the answer said: "All the denominators have the form n(n+1)." I think there was a typo in which there was a minus sign where there should have been a plus sign. Can you fix that?

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