<![CDATA[1991 AMC 8 Question 16]]>Q.16 1991 AMC8.jpg

When I follow the steps in the question, I first get rid of the top half. Then for step two, I get rid of the bottom row, which leaves me the third row. Then after the third step, I get rid of the right two numbers in row three. That leaves me only 9 and 10 after step three. Following the same logic and similar way of folding, why is the answer 9 instead of 10 when I fold over the left half?

]]>https://forum.poshenloh.com/topic/1050/1991-amc-8-question-16RSS for NodeMon, 11 May 2026 02:21:54 GMTSat, 06 Aug 2022 03:55:41 GMT60<![CDATA[Reply to 1991 AMC 8 Question 16 on Sat, 08 Oct 2022 03:54:25 GMT]]>Thanks for the explanation. I guess I didn’t think that the card had numbers on both sides. But it makes sense now.

]]>https://forum.poshenloh.com/post/5474https://forum.poshenloh.com/post/5474Sat, 08 Oct 2022 03:54:25 GMT<![CDATA[Reply to 1991 AMC 8 Question 16 on Mon, 12 Sep 2022 04:10:34 GMT]]>@magnificenthorse

Hi! This is a very interesting question, and I'm not really sure how to do it, but when I cut the picture out and played with it, I seemed to get 9 too.

I think it's because when you do Step 1, you don't get rid of the top half, instead, what remains is the top half. WechatIMG3.jpeg WechatIMG4.jpeg
(BTW: I labeled both sides of the paper with the numbers. so like, on the back of the 1 I wrote another 1.)

Same for Step 2, I think. What you get is the bottom row.
For Step 3, I get 12 and 11 from the third row.
And lastly, for Step 4, I get 9.
WechatIMG5.jpeg
WechatIMG6.jpeg
WechatIMG7.jpeg

]]>https://forum.poshenloh.com/post/5459https://forum.poshenloh.com/post/5459Mon, 12 Sep 2022 04:10:34 GMT<![CDATA[Reply to 1991 AMC 8 Question 16 on Mon, 12 Sep 2022 00:18:54 GMT]]>Wow this question has been sitting around for a long time. If anyone knows how to do this, pls help ASAP.

]]>https://forum.poshenloh.com/post/5458https://forum.poshenloh.com/post/5458Mon, 12 Sep 2022 00:18:54 GMT