Therefore, the answer is \(\dfrac{\binom{8}{2}\binom{6}{2}\binom{4}{2}}{4!}=\boxed{105}.\)

]]>Yeah Prof Loh explained in the vid I think.

Also when I was doing the four 4's problem (arrange four 4's and add operations or "smush" - Prof Loh word - them together to get any number from 1-50) I started using !! like mad - around 3/4 of the time (and I was the only person in the class using it frequently) ]]>