Subcategories

• Day 13

  Working Together

  Module 1 Day 13 Challenge Part 1 Module 1 Day 13 Challenge Part 2 Module 1 Day 13 Your Turn Part 1 Module 1 Day 13 Your Turn Part 2 Module 1 Day 13 Your Turn Part 3 Module 1 Day 13 Your Turn Part 4 Module 1 Day 13 Your Turn Part 5
  4
  Topics
  13
  Posts

  R

  111,111/11 = 10101
  111,111/13 = 8547

• Day 14

  100 Bottles

  Module 1 Day 14 Challenge Part 1 Module 1 Day 14 Challenge Part 2 Module 1 Day 14 Your Turn Part 1 Module 1 Day 14 Your Turn Part 2
  0
  Topics
  0
  Posts
  No new posts.
• Day 15

  Harmonic Mean

  Module 1 Day 15 Challenge Part 1 Module 1 Day 15 Challenge Part 2 Module 1 Day 15 Challenge Part 3 Module 1 Day 15 Challenge Part 4 Module 1 Day 15 Your Turn Part 1 Module 1 Day 15 Your Turn Part 2 Module 1 Day 15 Your Turn Part 3 Module 1 Day 15 Your Turn Part 4
  7
  Topics
  25
  Posts

  F

  @quacker88 Hi! Thanks for the helpful explanation because I had the same question victorioussheep did. It's just when I tried to solve the problem you gave, I got the answer B/(B-A).

  (1/A-1/B)t=1 Simplifying (1/A-1/B), I get (B-A/AB)t=1 and so t= AB/B-A. t is the time it takes for the first runner to catch up with the second runner. So the number of laps the first runner runs is AB/B-A divided by A which is B/B-A.

  Also, I think how Prof. Loh got A/A-B was by solving for the number of laps the trainer or the second runner was running.

  I don't know if this is correct, but I hope you can look over my work. Thanks!

• Day 16

  Changing Speed

  Module 1 Day 16 Challenge Part 1 Module 1 Day 16 Challenge Part 2 Module 1 Day 16 Challenge Part 3 Module 1 Day 16 Challenge Part 4 Module 1 Day 16 Your Turn Part 1 Module 1 Day 16 Your Turn Part 2
  3
  Topics
  7
  Posts

  D

  @userusername Thanks so much for letting us know! I've fixed this now. 🙂